5x^2-288x+448=0

Solution for 5x^2-288x+448=0 equation:

5x^2-288x+448=0

a = 5; b = -288; c = +448;
Δ = b2-4ac
Δ = -2882-4·5·448
Δ = 73984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{73984}=272$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-288)-272}{2*5}=\frac{16}{10}
=1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-288)+272}{2*5}=\frac{560}{10}
=56
$